Use the Table of Values of F to Estimate the Limit

Multiple Choice

Use the table of values of f to estimate the limit.
- $\text { Let } f(x) =x^{2}+8 x-2, \text { find } \lim _{x \rightarrow 2} f(x)$
$\begin{array}{c|l|l|l|l|l|l}\mathrm{x} & 1.9 & 1.99 & 1.999 & 2.001 & 2.01 & 2.1 \\\hline \mathrm{f}(\mathrm{x}) & & & & & &\end{array}$

A)
$\begin{array}{c|ccrrcc}\mathrm{x} & 1.9 & 1.99 & 1.999 & 2.001 & 2.01 & 2.1 \\\hline \mathrm{f}(\mathrm{x}) & 16.692 & 17.592 & 17.689 & 17.710 & 17.808 & 18.789\end{array} \text {; limit }=17.70$

B)
$\begin{array}{c|ccrrcc}\mathrm{x} & 1.9 & 1.99 & 1.999 & 2.001 & 2.01 & 2.1 \\\hline \mathrm{f}(\mathrm{x}) & 16.810 & 17.880 & 17.988 & 18.012 & 18.120 & 19.210\end{array} \text {; limit }=18.0$

C)
$\begin{array}{c|llllll}\mathrm{x} & 1.9 & 1.99 & 1.999 & 2.001 & 2.01 & 2.1 \\\hline \mathrm{f}(\mathrm{x}) & 5.043 & 5.364 & 5.396 & 5.404 & 5.436 & 5.763\end{array} \text {; limit }=\infty$

D)
$\begin{array}{c|llllll}\mathrm{x} & 1.9 & 1.99 & 1.999 & 2.001 & 2.01 & 2.1 \\\hline \mathrm{f}(\mathrm{x}) & 5.043 & 5.364 & 5.396 & 5.404 & 5.436 & 5.763\end{array} \text {; limit }=5.40$