$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$

Multiple Choice

$\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }$
- $$\lim _ { x \rightarrow 1 ^ { + } } \left( \frac { x } { x + 9 } \right) \left( \frac { - 3 x + 8 } { x ^ { 2 } + 9 x } \right)$$

A) Does not exist
B) $\frac { 11 } { 82 }$
C) $\frac { 11 } { 64 }$
D) $\frac { 1 } { 11 }$