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 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }

Question 26

Multiple Choice

 Find the limit using limx=0sinxx=1\text { Find the limit using } \lim _ { x = 0 } \frac { \sin x } { x } = 1 \text {. }
- limx2+(x+5) (x+2x+2) \lim _ { x \rightarrow 2 ^ { + } } ( x + 5 ) \left( \frac { | x + 2 | } { x + 2 } \right)


A) Does not exist
B) 3
C) 3- 3
D) 7

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