Solved

Find a Formula for the Nth Term of the Sequence 1,14,19,116,1251 , - \frac { 1 } { 4 } , \frac { 1 } { 9 } , - \frac { 1 } { 16 } , \frac { 1 } { 25 }

Question 51

Multiple Choice

Find a formula for the nth term of the sequence.
- 1,14,19,116,1251 , - \frac { 1 } { 4 } , \frac { 1 } { 9 } , - \frac { 1 } { 16 } , \frac { 1 } { 25 } (reciprocals of squares with alternating signs)


A) an=(1) n2n2a _ { n } = \frac { ( - 1 ) ^ { n ^ { 2 } } } { n ^ { 2 } }
B) an=(1) nn2a _ { n } = \frac { ( - 1 ) ^ { n } } { n ^ { 2 } }
C) an=(1) 2n+1n2a _ { n } = \frac { ( - 1 ) ^ { 2 n + 1 } } { n ^ { 2 } }
D) an=(1) n+1n2a _ { n } = \frac { ( - 1 ) ^ { n + 1 } } { n ^ { 2 } }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions