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By Using a Graphing Utility Select the Correct Graph of the Polar

Question 90

Multiple Choice

By using a graphing utility select the correct graph of the polar equation. Identify the graph. $\frac { 11 } { 11 + 16 \sin \theta }$

A)
$By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 11 } { 11 + 16 \sin \theta } A) e= \frac{16}{11}>1 \Rightarrow Hyperabola B) e= \frac{16}{11}>1 \Rightarrow Hyperabola C) e= \frac{16}{11}>1 \Rightarrow Hyperabola D) e= \frac{16}{11}>1 \Rightarrow Hyperabola E) e= \frac{16}{11}>1 \Rightarrow Hyperabola$
$e= \frac{16}{11}>1 \Rightarrow$ Hyperabola
B)
$By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 11 } { 11 + 16 \sin \theta } A) e= \frac{16}{11}>1 \Rightarrow Hyperabola B) e= \frac{16}{11}>1 \Rightarrow Hyperabola C) e= \frac{16}{11}>1 \Rightarrow Hyperabola D) e= \frac{16}{11}>1 \Rightarrow Hyperabola E) e= \frac{16}{11}>1 \Rightarrow Hyperabola$
$e= \frac{16}{11}>1 \Rightarrow$ Hyperabola
C)
$By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 11 } { 11 + 16 \sin \theta } A) e= \frac{16}{11}>1 \Rightarrow Hyperabola B) e= \frac{16}{11}>1 \Rightarrow Hyperabola C) e= \frac{16}{11}>1 \Rightarrow Hyperabola D) e= \frac{16}{11}>1 \Rightarrow Hyperabola E) e= \frac{16}{11}>1 \Rightarrow Hyperabola$
$e= \frac{16}{11}>1 \Rightarrow$ Hyperabola
D)
$By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 11 } { 11 + 16 \sin \theta } A) e= \frac{16}{11}>1 \Rightarrow Hyperabola B) e= \frac{16}{11}>1 \Rightarrow Hyperabola C) e= \frac{16}{11}>1 \Rightarrow Hyperabola D) e= \frac{16}{11}>1 \Rightarrow Hyperabola E) e= \frac{16}{11}>1 \Rightarrow Hyperabola$
$e= \frac{16}{11}>1 \Rightarrow$ Hyperabola
E)
$By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 11 } { 11 + 16 \sin \theta } A) e= \frac{16}{11}>1 \Rightarrow Hyperabola B) e= \frac{16}{11}>1 \Rightarrow Hyperabola C) e= \frac{16}{11}>1 \Rightarrow Hyperabola D) e= \frac{16}{11}>1 \Rightarrow Hyperabola E) e= \frac{16}{11}>1 \Rightarrow Hyperabola$
$e= \frac{16}{11}>1 \Rightarrow$ Hyperabola

By Using a Graphing Utility Select the Correct Graph of the Polar

Multiple Choice

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