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Find the Standard Form of the Equation of the Ellipse x24y216=1\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 16 } = 1

Question 86

Multiple Choice

Find the standard form of the equation of the ellipse with the given characteristics and center at the origin.  Find the standard form of the equation of the ellipse with the given characteristics and center at the origin.   A)   \frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 16 } = 1  B)   \frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 4 } = 1  C)   \frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 16 } = 1  D)   \frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 16 } = 1  E)   \frac { x } { 4 } + \frac { y } { 16 } = 1


A) x24y216=1\frac { x ^ { 2 } } { 4 } - \frac { y ^ { 2 } } { 16 } = 1
B) x24+y24=1\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 4 } = 1
C) x216+y216=1\frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 16 } = 1
D) x24+y216=1\frac { x ^ { 2 } } { 4 } + \frac { y ^ { 2 } } { 16 } = 1
E) x4+y16=1\frac { x } { 4 } + \frac { y } { 16 } = 1

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