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Find the Standard Form of the Equation of the Hyperbola  Vertices: (±4,0); asymptotes: y=±6x\text { Vertices: } ( \pm 4,0 ) ; \text { asymptotes: } y = \pm 6 x

Question 23

Multiple Choice

Find the standard form of the equation of the hyperbola with the given characteristics and center at the origin.  Vertices: (±4,0) ; asymptotes: y=±6x\text { Vertices: } ( \pm 4,0 ) ; \text { asymptotes: } y = \pm 6 x


A) x216y2576=1\frac { x ^ { 2 } } { 16 } - \frac { y ^ { 2 } } { 576 } = 1
B) y216x2576=1\frac { y ^ { 2 } } { 16 } - \frac { x ^ { 2 } } { 576 } = 1
C) y2576x216=1\frac { y ^ { 2 } } { 576 } - \frac { x ^ { 2 } } { 16 } = 1
D) y216+x2576=1\frac { y ^ { 2 } } { 16 } + \frac { x ^ { 2 } } { 576 } = 1
E) x216+y2576=1\frac { x ^ { 2 } } { 16 } + \frac { y ^ { 2 } } { 576 } = 1

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