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By Using a Graphing Utility Select the Correct Graph of the Polar

Question 43

Multiple Choice

By using a graphing utility select the correct graph of the polar equation. Identify the graph. 1414+18sin⁡θ\frac { 14 } { 14 + 18 \sin \theta }


A)
By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 14 } { 14 + 18 \sin \theta } A) e=\frac{9}{7}>1 \Rightarrow Hyperabola B) e=\frac{9}{7}>1 \Rightarrow Hyperabola C) e=\frac{9}{7}>1 \Rightarrow Hyperabola D) e=\frac{9}{7}>1 \Rightarrow Hyperabola E) e=\frac{9}{7}>1 \Rightarrow Hyperabola
e=97>1⇒ e=\frac{9}{7}>1 \Rightarrow Hyperabola
B)
By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 14 } { 14 + 18 \sin \theta } A) e=\frac{9}{7}>1 \Rightarrow Hyperabola B) e=\frac{9}{7}>1 \Rightarrow Hyperabola C) e=\frac{9}{7}>1 \Rightarrow Hyperabola D) e=\frac{9}{7}>1 \Rightarrow Hyperabola E) e=\frac{9}{7}>1 \Rightarrow Hyperabola
e=97>1⇒ e=\frac{9}{7}>1 \Rightarrow Hyperabola
C)
By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 14 } { 14 + 18 \sin \theta } A) e=\frac{9}{7}>1 \Rightarrow Hyperabola B) e=\frac{9}{7}>1 \Rightarrow Hyperabola C) e=\frac{9}{7}>1 \Rightarrow Hyperabola D) e=\frac{9}{7}>1 \Rightarrow Hyperabola E) e=\frac{9}{7}>1 \Rightarrow Hyperabola
e=97>1⇒ e=\frac{9}{7}>1 \Rightarrow Hyperabola
D)
By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 14 } { 14 + 18 \sin \theta } A) e=\frac{9}{7}>1 \Rightarrow Hyperabola B) e=\frac{9}{7}>1 \Rightarrow Hyperabola C) e=\frac{9}{7}>1 \Rightarrow Hyperabola D) e=\frac{9}{7}>1 \Rightarrow Hyperabola E) e=\frac{9}{7}>1 \Rightarrow Hyperabola
e=97>1⇒ e=\frac{9}{7}>1 \Rightarrow Hyperabola
E)
By using a graphing utility select the correct graph of the polar equation. Identify the graph. \frac { 14 } { 14 + 18 \sin \theta } A) e=\frac{9}{7}>1 \Rightarrow Hyperabola B) e=\frac{9}{7}>1 \Rightarrow Hyperabola C) e=\frac{9}{7}>1 \Rightarrow Hyperabola D) e=\frac{9}{7}>1 \Rightarrow Hyperabola E) e=\frac{9}{7}>1 \Rightarrow Hyperabola
e=97>1⇒ e=\frac{9}{7}>1 \Rightarrow Hyperabola

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