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    Multivariable Calculus International
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    Exam 4: Applications of Differentiation
  5. Question
    Use the Midpoint Rule With\(n = 6\) To Approximate the Integral
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Use the Midpoint Rule With n=6n = 6n=6 To Approximate the Integral

Question 56

Question 56

Short Answer

Use the Midpoint Rule with n=6n = 6n=6 to approximate the integral. Round the answer to 3 decimal places.
∫0122sin⁡tdt\int _ { 0 } ^ { 12 } 2 \sin \sqrt { t } d t∫012​2sint​dt

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