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Find the Integral Using an Appropriate Trigonometric Substitution $\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x$

Question 138

Short Answer

Find the integral using an appropriate trigonometric substitution.
$\int \frac { x ^ { 3 } } { \sqrt { x ^ { 2 } + 36 } } d x$

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