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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) 2cos2x+sinx=12 \cos ^ { 2 } x + \sin x = 1

Question 45

Short Answer

Solve the equation in the interval [0,2π)[ 0,2 \pi )
. 2cos2x+sinx=12 \cos ^ { 2 } x + \sin x = 1

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