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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) tanxcosxcosx=0\tan x \cos x - \cos x = 0

Question 22

Multiple Choice

Solve the equation in the interval [0,2π) [ 0,2 \pi ) . tanxcosxcosx=0\tan x \cos x - \cos x = 0


A) x=π4x = \frac { \pi } { 4 } , x=3π4x = \frac { 3 \pi } { 4 } , x=π2x = \frac { \pi } { 2 } , x=3π2x = \frac { 3 \pi } { 2 }

B) x=0x = 0 , x=π2x = \frac { \pi } { 2 } , x=π4x = \frac { \pi } { 4 } , x=5π4x = \frac { 5 \pi } { 4 } , x=3π2x = \frac { 3 \pi } { 2 }

C) x=0x = 0 , x=π2x = \frac { \pi } { 2 } , x=3π4x = \frac { 3 \pi } { 4 }

D) x=π2x = \frac { \pi } { 2 } , x=3π4x = \frac { 3 \pi } { 4 } , x=5π4x = \frac { 5 \pi } { 4 }

E) x=0x = 0 , x=π2x = \frac { \pi } { 2 }

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