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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) sinx=cosx\sin x = \cos x

Question 65

Multiple Choice

Solve the equation in the interval [0,2π) [ 0,2 \pi ) . sinx=cosx\sin x = \cos x


A) x=π4x = \frac { \pi } { 4 } , x=5π4x = \frac { 5 \pi } { 4 }

B) x=3π4x = \frac { 3 \pi } { 4 } , x=5π4x = \frac { 5 \pi } { 4 }

C) x=π4x = \frac { \pi } { 4 } , x=7π4x = \frac { 7 \pi } { 4 }

D) x=5π4x = \frac { 5 \pi } { 4 } , x=7π4x = \frac { 7 \pi } { 4 }

E) none

Correct Answer:

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