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Solve the Equation in the Interval [0,2π)[ 0,2 \pi ) sin⁡x=cos⁡2x\sin x = \cos 2 x

Question 31

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Solve the equation in the interval [0,2π)[ 0,2 \pi ) . sin⁡x=cos⁡2x\sin x = \cos 2 x

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