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Find the Mean, Variance, and Standard Deviation of the Uniform f(x)=118f ( x ) = \frac { 1 } { 18 }

Question 32

Multiple Choice

Find the mean, variance, and standard deviation of the uniform distribution f(x) =118f ( x ) = \frac { 1 } { 18 } over the interval [0, 18] without using integration.


A)  expected value (mean)  : 9.000 variance: 27.000 standard deviation: 5.196\begin{array} { l l } \text { expected value (mean) : } & 9.000 \\\text { variance: } & 27.000 \\\text { standard deviation: } & 5.196\end{array}
B)  expected value (mean)  : 27.000 variance: 9.000 standard deviation: 5.196\begin{array} { l l } \text { expected value (mean) : } & 27.000 \\\text { variance: } & 9.000 \\\text { standard deviation: } & 5.196\end{array}
C)  expected value (mean)  : 27.000 variance: 5.196 standard deviation: 9.000\begin{array} { l l } \text { expected value (mean) : } & 27.000 \\\text { variance: } & 5.196 \\\text { standard deviation: } & 9.000\end{array}
D)  expected value (mean)  :5.196 variance: 9.000 standard deviation: 27.000\begin{array} { l l } \text { expected value (mean) } : & 5.196 \\\text { variance: } & 9.000 \\\text { standard deviation: } & 27.000\end{array}
E)  expected value (mean)  9.000 variance: 5.196 standard deviation: 27.000\begin{array} { l l } \text { expected value (mean) } & 9.000 \\\text { variance: } & 5.196 \\\text { standard deviation: } & 27.000\end{array}

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