Find Pk+1 for the Given Pk $P _ { k } = \frac { 6 } { k ( k + 1 ) }$

Multiple Choice

Find Pk+1 for the given Pk. $P _ { k } = \frac { 6 } { k ( k + 1 ) }$

A) $P _ { k + 1 } = \frac { 6 } { k ( k + 1 ) } + 1$
B) $P _ { k + 1 } = \frac { 6 } { k ( k + 1 ) } + \frac { 6 } { ( k + 1 ) ( k + 2 ) }$
C) $P _ { k + 1 } = \frac { 6 } { ( k + 1 ) ( k + 2 ) }$
D) $P _ { k + 1 } = \frac { 6 } { k ( k + 2 ) }$
E) $P _ { k + 1 } = \frac { 36 } { ( k + 1 ) ( k + 2 ) }$