Solve the System of Linear Equations $\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 3 \\16 x + 40 y & = 6 \\24 x + 8 y - 16 z & = - 3\end{array} \right.$

Multiple Choice

Solve the system of linear equations $\left\{ \begin{array} { l l } - 8 x + 24 y + 8 z & = 3 \\16 x + 40 y & = 6 \\24 x + 8 y - 16 z & = - 3\end{array} \right.$ using an inverse matrix.

A) $\left[ \begin{array} { c } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } - \frac { 3 } { 8 } \\0 \\\frac { 9 } { 8 }\end{array} \right]$
B) $\left[ \begin{array} { c } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } 0 \\\frac { 3 } { 4 } \\~- \frac { 3 } { 8 }\end{array} \right]$
C) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { c } \frac { 3 } { 8 } \\\\- \frac { 9 } { 8 } \\\\\frac { 3 } { 4 }\end{array} \right]$
D) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { l } \frac { 3 } { 8 } \\0 \\\frac { 3 } { 4 }\end{array} \right]$
E) $\left[ \begin{array} { l } x \\y \\z\end{array} \right] = \left[ \begin{array} { r } - \frac { 3 } { 8 } \\\\- \frac { 9 } { 8 } \\\\- \frac { 3 } { 4 }\end{array} \right]$