An Industrial Psychologist Has Determined That the Average Percent Score $P = \frac { 100 } { 1 + 24 e ^ { - 0.15 t } }$

Multiple Choice

An industrial psychologist has determined that the average percent score for an employee on a test of the employee's knowledge of the company's product is given by $P = \frac { 100 } { 1 + 24 e ^ { - 0.15 t } }$ where t is the number of weeks on the job and P is the percent score. Estimate (to the nearest week) the expected number of weeks of employment that are necessary for an employee to earn a 85% score on the test.

A) 38 weeks
B) 37 weeks
C) 42 weeks
D) 60 weeks
E) 33 weeks