Find (Fg)(x) $f ( x ) = \sqrt { 2 x }$

Multiple Choice

Find (fg) (x) . $f ( x ) = \sqrt { 2 x }$ $g ( x ) = \sqrt { - x + 3 }$

A) $( f g ) ( x ) = x \sqrt { - 2 } + \sqrt { 6 x }$
B) $( f g ) ( x ) = x \sqrt { - 2 + 6 x }$
C) $( f g ) ( x ) = \sqrt { x + 3 }$
D) $( f g ) ( x ) = \sqrt { - 2 x ^ { 2 } + 3 }$
E) $( f g ) ( x ) = \sqrt { - 2 x ^ { 2 } + 6 x }$