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Current Through a Capacitor with Capacitance of 0 μF\mu \mathrm { F }

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current through a capacitor with capacitance of 0.68 is given by i(t) = 4 μF\mu \mathrm { F } sin(2π×1500t)u(t)mA\sin ( 2 \pi \times 1500 t ) u ( t ) \mathrm { mA } . Find the voltage across the capacitor v(t)\mathrm { v } ( \mathrm { t } ) and plot the current and voltage as a function of time.

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