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Voltage Across a Capacitor with Capacitance of 39 Is Given μF\mu \mathrm { F }

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voltage across a capacitor with capacitance of 39 is given by μF\mu \mathrm { F } v(t)={30t,0t<590t600,5t<1060t+900,10t<150, otherwise v ( t ) = \left\{ \begin{array} { c } - 30 t , \quad 0 \leq t < 5 \\90 t - 600 , \quad 5 \leq t < 10 \\- 60 t + 900 , \quad 10 \leq t < 15 \\0 , \quad \text { otherwise }\end{array} \right. Find the current through the capacitor i(t) and plot the voltage and current as a function of time.

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