In the Circuit Shown Below, Let
Use Mesh Analysis to Find Mesh Currents

Question

In the Circuit Shown Below, Let 
Use Mesh Analysis to Find Mesh Currents

Examlex · Accepted Answer

The Answer is

\begin{array} { l } I _ { 1 } = I _ { 1 } 1 \R _ { 1 } \left( I _ { 2 } - I _ { 1 } ight) + R _ { 3 } I _ { 2 } + R _ { 2 } \left( I _ { 2 } - I _ { 3 } ight) = 0 \I _ { 3 } = - I _ { 2 } 2 \V _ { 2 } = R _ { 4 } \left( I _ { 1 } - I _ { 3 } ight) \V _ { 1 } = V _ { 2 } + R _ { 1 } \left( I _ { 1 } - I _ { 2 } ight) \V _ { 3 } = V _ { 1 } - R _ { 3 } I _ { 2 } \I _ { 1 } = 5 \mathrm {~mA} , I _ { 2 } = 1.3333 \mathrm {~mA} , I _ { 3 } = - 2 \mathrm {~mA} , V _ { 1 } = 7.8667 \mathrm {~V} , V _ { 2 } = 4.2 \mathrm {~V} , V _ { 3 } = 5.8667 \mathrm {~V}\end{array}

% Mesh Analysis clear all
Isl

= 0.005 ; I s 2 = 0.002

;

R 1 = 1000 ; R 2 = 500 ; R 3 = 1500 ; R 4 = 600

;
syms I1 I2 I3

[ I 1 , I 2 , I 3 ] = s 01 v e ( R 1 * ( I 2 - I 1 ) + R 3 * I 2 + R 2 * ( I 2 - I 3 ) , \ldots

I 1 = I s 1 , I 3 = - I s 2 , I 1 , I 2 , I 3 )

V 2 = R 4 ^ { * } ( I 1 - I 3 angle

V 1 = V 2 + R 1 * ( I 1 - I 2 )

V 3 = V 1 - R 3 * I 2

IR

4 = I 1 - I 3

I R 1 = I 1 - I 2

I R 2 = - I 3 + I 2

IR3

= I 2

S u m I = - I R 1 - I R 2 + I R 4

I 1 = \operatorname { vpa } ( I 1,7 )

I 2 = \operatorname { vpa } ( \mathrm { I } 2,7 )

\mathrm { I } 3 = \mathrm { vpa } ( \mathrm { I } 3,7 )

\mathrm { V } 1 = \operatorname { vpa } ( \mathrm { V } , 7 )

\mathrm { V } 2 = \mathrm { Vpa } ( \mathrm { V } 2,7 )

\mathrm { V } 3 = \mathrm { VPa } ( \mathrm { V } 3,7 )

IR

4 =

vpa (IR4, 7)
IR1=vpa (IR1, 7)
IR2=vpa (IR2, T)
IR3=ypa (IR3, 7)
SumI=vpa (SumI, 7) Answers:

\begin{array} { l } I 1 = \0.005 \I 2 = \0.001333333 \I 3 = \- 0.002 \V 1 = \7.866667 \V 2 = \4.2 \V 3 = \5.866667\end{array}

Essay