Solved

The Electrostatic Force ( F ) Between Two Plates of a Charged

Question 50

Multiple Choice

The electrostatic force ( F ) between two plates of a charged capacitor is directly proportional to the product of the charges ( q1q_ 1 and q2q_2 ) on each plate and inversely proportional to the square of the distance ( d ) between the plates.


A) F=q1dq2F = \frac { q _ { 1 } } { d q _ { 2 } }
B) F=dq1q2F = \frac { d } { q 1 q 2 }
C) F=q1q2dF = \frac { q 1 q 2 } { d }
D) F=q1q2d2F = \frac { q 1 q 2 } { d ^ { 2 } }

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions