Use the Frequency Distribution to Find the Mean and the Sample

Multiple Choice

Use the frequency distribution to find the mean and the sample standard deviation. Does the data form a normal distribution? Remember: if the data fall within 2% of the empirical rule of 68%, 95%, and 99.7% for one, two, or three standard deviations, respectively, they form a normal distribution.   $\begin{array}{|ll|}\hline \text { Life of bulb (hours) } & \text { Frequency t} \\\hline 0-999 . 5 & 103 \\999.5-1,999.5 & 476 \\1,999.5-2,999.5 & 2,062 \\2,999.5-3,999.5 & 4,129 \\3,999.5-4,999.5 & 2,460 \\4,999.5-5,999.5 & 421 \\5,999.5-6,999.5 & 146 \\\hline\end{array}$

A) The mean is 3,546 hours. The sample standard deviation is 1,018 hours. The data forms a normal distribution.
B) The mean is 3,523 hours. The sample standard deviation is 1,017 hours. The data forms a normal distribution.
C) The mean is 3,546 hours. The sample standard deviation is 1,018 hours. The data doesn't form a normal distribution.
D) The mean is 3,542 hours. The sample standard deviation is 1,027 hours. The data forms a normal distribution.
E) The mean is 3,523 hours. The sample standard deviation is 1,017 hours. The data doesn't form a normal distribution.