Solve the System $\begin{array}{l}(4 x+3 y-3 z=29) \\x-5 z=12 \\5 x+5 z=0 \\\end{array}$

Multiple Choice

Solve the system. $\begin{array}{l}(4 x+3 y-3 z=29) \\x-5 z=12 \\5 x+5 z=0 \\\end{array}$

A) x = 2, y = 5, z = -2
B) x = 3, y = 5, z = -3
C) x = 3, y = 4, z = -2
D) x = 2, y = 6, z = -3