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Solve the System (x5y+2z=242x+2y+4z=122x2y3z=4)\left(\begin{array}{llll}x&-&5 y&+&2 z & = & 24 \\2 x&+&2 y&+&4 z & = & 12 \\2 x&-&2 y&-&3 z & = & -4\end{array}\right)

Question 144

Multiple Choice

Solve the system. (x5y+2z=242x+2y+4z=122x2y3z=4) \left(\begin{array}{llll}x&-&5 y&+&2 z & = & 24 \\2 x&+&2 y&+&4 z & = & 12 \\2 x&-&2 y&-&3 z & = & -4\end{array}\right)


A) x = 1, y = -6, z = 3
B) x = 0, y = -4, z = 1
C) x = 0, y = -7, z = 1
D) x = 1, y = -3, z = 4

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