Laws that deal with electrical currents are known as Kirchhoff s Laws. When Kirchhoff s Laws are applied to the electrical network shown in the figure, where

R _ { 1 } = 4

ohms,

R _ { 2 } = 2

ohms,

R _ { 3 } = 4

ohms,

V _ { 1 } = 26

volts,

V _ { 2 } = 14

volts, the currents

I _ { 1 } , I _ { 2 }

and

I _ { 3 }

(in amps)are the solution of the system

\left\{ \begin{array} { l } I _ { 1 } + I _ { 2 } - I _ { 3 } = 0 \\4 I _ { 1 } + 2 I _ { 3 } = 26 \\4 I _ { 1 } - 4 I _ { 2 } = 12\end{array} \right.

$Laws that deal with electrical currents are known as Kirchhoff s Laws. When Kirchhoff s Laws are applied to the electrical network shown in the figure, where R _ { 1 } = 4 ohms, R _ { 2 } = 2 ohms, R _ { 3 } = 4 ohms, V _ { 1 } = 26 volts, V _ { 2 } = 14 volts, the currents I _ { 1 } , I _ { 2 } and I _ { 3 } (in amps)are the solution of the system \left\{ \begin{array} { l } I _ { 1 } + I _ { 2 } - I _ { 3 } = 0 \\ 4 I _ { 1 } + 2 I _ { 3 } = 26 \\ 4 I _ { 1 } - 4 I _ { 2 } = 12 \end{array} \right. Find the current I _ { 3 } . A) 6 amps B) 5 amps C) 8 amps D) 7 amps E) 4 amps$ Find the current

I _ { 3 }

.
A)

6

amps
B) 5 amps
C)

8

amps
D)

7

amps
E)

4

amps

Evaluate the Determinant of the Matrix [68−5−738−8−25]\left[ \begin{array} { c c c } 6 & 8 & - 5 \\- 7 & 3 & 8 \\- 8 & - 2 & 5\end{array} \right]​6−7−8​83−2​−585​​

Multiple Choice

Correct Answer:VerifiedShow Answer

Evaluate the Determinant of the Matrix $\left[ \begin{array} { c c c } 6 & 8 & - 5 \\- 7 & 3 & 8 \\- 8 & - 2 & 5\end{array} \right]$

Correct Answer:
Verified