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The Ratio of the Width, W , of the Temple wh=2h51\frac { w } { h } = \frac { 2 h } { \sqrt { 5 } - 1 }

Question 110

Multiple Choice

The ratio of the width, w , of the Temple of Hephaestus to its height, h , is wh=2h51\frac { w } { h } = \frac { 2 h } { \sqrt { 5 } - 1 } . This number is called the golden section. Early Greeks believed that the most aesthetically pleasing rectangle had this ratio. If the height is 5 , find the width. Rationalize the denominator and simplify the expression.  The ratio of the width, w , of the Temple of Hephaestus to its height, h , is  \frac { w } { h } = \frac { 2 h } { \sqrt { 5 } - 1 }  . This number is called the golden section. Early Greeks believed that the most aesthetically pleasing rectangle had this ratio. If the height is 5 , find the width. Rationalize the denominator and simplify the expression.   A)   \frac { 5 \sqrt { 5 } } { 2 }  B)   \frac { \sqrt { 5 } + 5 } { 2 }  C)   \frac { 5 \sqrt { 5 } - 5 } { 2 }  D)   \frac { 5 \sqrt { 5 } + 5 } { 4 }  E)   \frac { 5 \sqrt { 5 } + 5 } { 2 }


A) 552\frac { 5 \sqrt { 5 } } { 2 }
B) 5+52\frac { \sqrt { 5 } + 5 } { 2 }
C) 5552\frac { 5 \sqrt { 5 } - 5 } { 2 }
D) 55+54\frac { 5 \sqrt { 5 } + 5 } { 4 }
E) 55+52\frac { 5 \sqrt { 5 } + 5 } { 2 }

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