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Graph the Solution to the Inequality on the Real Line $\frac { x + 4 } { 3 x + 3 } \leq 0$

Question 93

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Graph the solution to the inequality on the real line. $\frac { x + 4 } { 3 x + 3 } \leq 0$

A) $Graph the solution to the inequality on the real line. \frac { x + 4 } { 3 x + 3 } \leq 0 A) B) C) D) E) none of these$
B) $Graph the solution to the inequality on the real line. \frac { x + 4 } { 3 x + 3 } \leq 0 A) B) C) D) E) none of these$
C) $Graph the solution to the inequality on the real line. \frac { x + 4 } { 3 x + 3 } \leq 0 A) B) C) D) E) none of these$
D) $Graph the solution to the inequality on the real line. \frac { x + 4 } { 3 x + 3 } \leq 0 A) B) C) D) E) none of these$
E) none of these

Graph the Solution to the Inequality on the Real Line x+43x+3≤0\frac { x + 4 } { 3 x + 3 } \leq 03x+3x+4​≤0

Multiple Choice

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Graph the Solution to the Inequality on the Real Line $\frac { x + 4 } { 3 x + 3 } \leq 0$

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