The Area of the Surface Generated by Revolving the Curve $x ( t ) = 3 t , \quad y = \sqrt { 7 } t + 1$

Multiple Choice

The area of the surface generated by revolving the curve $x ( t ) = 3 t , \quad y = \sqrt { 7 } t + 1$ with $t \in [ 0,1 ]$ about the x-axis is

A) $256 \pi \ln 2$
B) $128 \pi \ln 2$
C) $64 \pi \ln 2$
D) $32 \pi \ln 2$
E) $16 \pi \ln 2$