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Let f(x)=x+2+3x1f ( x ) = x + 2 + \frac { 3 } { x - 1 }

Question 82

Multiple Choice

Let f(x) =x+2+3x1f ( x ) = x + 2 + \frac { 3 } { x - 1 } on [2,7][ 2,7 ] Then the set of all c in (2,7) guaranteed by the Mean Value Theorem is


A) {16}\{ 1 - \sqrt { 6 } \}
B) {1+6}\{ 1 + \sqrt { 6 } \}
C) {0}\{ 0 \}
D) {16,1+6}\{ 1 - \sqrt { 6 } , 1 + \sqrt { 6 } \}
E) {13,0,1+3}\{ 1 - \sqrt { 3 } , 0,1 + \sqrt { 3 } \}

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