Solved

Let r(t)=etcos(t)ietsin(t)j+(2t)2k\mathbf { r } ( t ) = e ^ { t } \cos ( t ) \mathbf { i } - e ^ { t } \sin ( t ) \mathbf { j } + ( 2 - t ) ^ { 2 } \mathbf { k }

Question 5

Multiple Choice

Let r(t) =etcos(t) ietsin(t) j+(2t) 2k\mathbf { r } ( t ) = e ^ { t } \cos ( t ) \mathbf { i } - e ^ { t } \sin ( t ) \mathbf { j } + ( 2 - t ) ^ { 2 } \mathbf { k } Then r(0) \mathbf { r } ^ { \prime } ( 0 ) is


A) ij+4k\mathbf { i } - \mathbf { j } + 4 \mathbf { k }
B) ij4k\mathbf { i } - \mathbf { j } - 4 \mathbf { k }
C) i+j4k\mathbf { i } + \mathbf { j } - 4 \mathbf { k }
D) ij+4k- \mathbf { i } - \mathbf { j } + 4 \mathbf { k }
E) i+j4k- \mathbf { i } + \mathbf { j } - 4 \mathbf { k }

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