Multiple Choice
The voltage v across a 4 H pure inductor varies with time t according to the equation v = 18 sin (2π x
1000t - 30º) V. The current through the capacitor will thus be:
A) i = 18 sin (2π x 1000t - 30º) mA
B) i = 18 sin (2π x 1000t - 120º) mA
C) i = 0.72 sin (2π x 1000t - 30º) mA
D) i = 0.72 sin (2π x 1000t - 120º) mA
Correct Answer:

Verified
Correct Answer:
Verified
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