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Find a Function with the Given Partial Derivatives fx=ycos(xy)\frac { \partial f } { \partial x } = y \cos ( x y )

Question 37

Multiple Choice

Find a function with the given partial derivatives fx=ycos(xy) \frac { \partial f } { \partial x } = y \cos ( x y ) and fy=xcos(xy) \frac { \partial f } { \partial y } = x \cos ( x y )


A) f(x,y) =cos(xy) f ( x , y ) = \cos ( x y )
B) f(x,y) =sin(xy) f ( x , y ) = \sin ( x y )
C) f(x,y) =sin(xy) f ( x , y ) = - \sin ( x y )
D) f(x,y) =cos(xy) f ( x , y ) = - \cos ( x y )

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