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Find an Equation of the Line Tangent to the Parametric

Question 87

Multiple Choice

Find an equation of the line tangent to the parametric space curve
r(t) = ( Find an equation of the line tangent to the parametric space curve r(t) = ( + 3t + 1) i + (2 - 7t j + (4sin(t) -3) k at the point on the curve corresponding to t = 0. A) r(u) = (1 + 3u) i + (2 - 7u) j + (- 3 + 4s) k, u R B) 3x - 7y + 4z -23 = 0 C) x + y + z = 0 D) r(u) = (3 + u) i + (-7 + 2u) j + (4 - 3u) k, u R E) x + 2y - 3z - 14 = 0 + 3t + 1) i + (2 - 7t j + (4sin(t) -3) k at the point on the curve corresponding to t = 0.


A) r(u) = (1 + 3u) i + (2 - 7u) j + (- 3 + 4s) k, u Find an equation of the line tangent to the parametric space curve r(t) = ( + 3t + 1) i + (2 - 7t j + (4sin(t) -3) k at the point on the curve corresponding to t = 0. A) r(u) = (1 + 3u) i + (2 - 7u) j + (- 3 + 4s) k, u R B) 3x - 7y + 4z -23 = 0 C) x + y + z = 0 D) r(u) = (3 + u) i + (-7 + 2u) j + (4 - 3u) k, u R E) x + 2y - 3z - 14 = 0 R
B) 3x - 7y + 4z -23 = 0
C) x + y + z = 0
D) r(u) = (3 + u) i + (-7 + 2u) j + (4 - 3u) k, u 11ee7b17_3372_5854_ae82_d19d2ea0c252_TB9661_11 R
E) x + 2y - 3z - 14 = 0

Correct Answer:

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