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Solve the Initial Value Problem + 2

Question 61

Multiple Choice

Solve the initial value problem Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t + 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t + 2y = 0; y(0) = 4, Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t (0) = -2.


A) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t - 6 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
B) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t - 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
C) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t + 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
D) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t + 6 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t
E) y(t) = 4 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t cos t + 2 Solve the initial value problem + 2 + 2y = 0; y(0) = 4, (0) = -2. A) y(t) = 4 cos t - 6 sin t B) y(t) = 4 cos t - 2 sin t C) y(t) = 4 cos t + 2 sin t D) y(t) = 4 cos t + 6 sin t E) y(t) = 4 cos t + 2 sin t sin t

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