Holly Has a Fair Coin and a 10-Sided Die$\$ 1$

Question

Examlex · Accepted Answer

The Answer is A.

P(\$ 1)=P(

heads

) * P(1,2)+P(

tails

) P(1,2,3,4,5,6,7)=\frac{1}{2}\left(\frac{2}{10}+\frac{7}{10} ight)=\frac{9}{20}

B.

P(

heads

\mid

mug

)=\frac{P( ext { heads } n ext { mug })}{P( ext { mug })}=\frac{P( ext { mug } \mid ext { heads }) P( ext { heads })}{P( ext { mug })}=\frac{\frac{8}{10} \frac{1}{2}}{\frac{9}{10}}=\frac{4}{9}

Holly Has a Fair Coin and a 10-Sided Die $\$ 1$