If the Source String MULTIMEDIA Is Now Encoded Using Arithmetic

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The Answer is $We need \log _{2}(r) bits to code the sequence of symbols, where r is the range for the last coded symbol. Here, r is \mathbf{0.0000000016} , so the result is then computed as \mathbf{29.21928095} and the average bits per symbol equals 2.921928095 . We note that this is exactly equal to the entropy of the source, so in this case arithmetic coding provides optimal performance.$
We need

\log _{2}(r)

bits to code the sequence of symbols, where

r

is the range for the last coded symbol. Here,

r

is

\mathbf{0.0000000016}

, so the result is then computed as

\mathbf{29.21928095}

and the average bits per symbol equals 2.921928095 . We note that this is exactly equal to the entropy of the source, so in this case arithmetic coding provides optimal performance.

If the Source String MULTIMEDIA Is Now Encoded Using Arithmetic

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If the Source String MULTIMEDIA Is Now Encoded Using Arithmetic

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Correct Answer:VerifiedShow Answer

Correct Answer:
Verified