Consider the following periodic function with period $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) b_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) b_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) b_{2 n}=0, b_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) b_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, b_{2 n-1}=0, n=1,2,3, \ldots E) b_{n}=0, n=1,2,3, \ldots$ :
F (t) = $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) b_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) b_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) b_{2 n}=0, b_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) b_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, b_{2 n-1}=0, n=1,2,3, \ldots E) b_{n}=0, n=1,2,3, \ldots$
F $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) b_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) b_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) b_{2 n}=0, b_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) b_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, b_{2 n-1}=0, n=1,2,3, \ldots E) b_{n}=0, n=1,2,3, \ldots$ = f (t)
The Fourier representation has the form $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) b_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) b_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) b_{2 n}=0, b_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) b_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, b_{2 n-1}=0, n=1,2,3, \ldots E) b_{n}=0, n=1,2,3, \ldots$
Which of these are the coefficients $Consider the following periodic function with period : F (t) = F = f (t) The Fourier representation has the form Which of these are the coefficients ? A) b_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots B) b_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots C) b_{2 n}=0, b_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots D) b_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, b_{2 n-1}=0, n=1,2,3, \ldots E) b_{n}=0, n=1,2,3, \ldots$ ?
A)

b_{n}=\frac{1}{(2 n-1) \pi}, n=1,2,3, \ldots

b_{n}=-\frac{2}{\pi} \cdot \frac{1}{2 n-1}, n=1,2,3, \ldots

b_{2 n}=0, b_{2 n-1}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, n=1,2,3, \ldots

b_{2 n}=-\frac{2}{\left(4 n^{2}-1\right) \pi}, b_{2 n-1}=0, n=1,2,3, \ldots

b_{n}=0, n=1,2,3, \ldots

Consider the Conduction of Heat in a Rod 30 Cm

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