Solved

A Pendulum Has a Length of 2 T=2πL32T=2 \pi \sqrt{\frac{L}{32}}
A)

Question 92

Multiple Choice

A pendulum has a length of 2.6 feet. Find its period. Use the formula T=2πL32T=2 \pi \sqrt{\frac{L}{32}} .


A) 1.79sec1.79 \mathrm{sec}
B) 0.9sec0.9 \mathrm{sec}
C) 1.27sec1.27 \mathrm{sec}
D) 2.24sec2.24 \mathrm{sec}

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Q87: The radius, <span class="ql-formula" data-value="r"><span

Q88: Solve. Check for extraneous solutions.<br>- <span

Q89: Multiply<br>- <span class="ql-formula" data-value="(\sqrt{13}+\sqrt{3})(\sqrt{3}+\sqrt{2})"><span class="katex"><span class="katex-mathml"><math

Q90: Expressions of the form <span

Q91: <span class="ql-formula" data-value="\sqrt[4]{768}"><span class="katex"><span class="katex-mathml"><math xmlns="http://www.w3.org/1998/Math/MathML"><semantics><mrow><mroot><mn>768</mn><mn>4</mn></mroot></mrow><annotation encoding="application/x-tex">\sqrt[4]{768}</annotation></semantics></math></span><span

Q93: If <span class="ql-formula" data-value="n"><span class="katex"><span

Q94: Add or subtract. Assume all variables

Q95: Rewrite as a radical expression and

Q96: A ssume all variables

Q97: Tell whether the statement is true