Solved

Graph the Ellipse $a$ And $b$
- $\frac{(x+2)^{2}}{9}+(y+1)^{2}=1$ A) Center $(-2,-1), a=3, b=1$

Question 89

Multiple Choice

Graph the ellipse. Give the coordinates of the center, as well as the values of $a$ and $b$ .
- $\frac{(x+2) ^{2}}{9}+(y+1) ^{2}=1$
$Graph the ellipse. Give the coordinates of the center, as well as the values of a and b . - \frac{(x+2) ^{2}}{9}+(y+1) ^{2}=1 A) center (-2,-1) , a=3, b=1 B) center (-2,-1) , a=1, b=3 C) center (-2,-1) , a=1, b=3 D) center (-2,-1) , a=3, b=1$

A) center $(-2,-1) , a=3, b=1$
$Graph the ellipse. Give the coordinates of the center, as well as the values of a and b . - \frac{(x+2) ^{2}}{9}+(y+1) ^{2}=1 A) center (-2,-1) , a=3, b=1 B) center (-2,-1) , a=1, b=3 C) center (-2,-1) , a=1, b=3 D) center (-2,-1) , a=3, b=1$
B) center $(-2,-1) , a=1, b=3$
$Graph the ellipse. Give the coordinates of the center, as well as the values of a and b . - \frac{(x+2) ^{2}}{9}+(y+1) ^{2}=1 A) center (-2,-1) , a=3, b=1 B) center (-2,-1) , a=1, b=3 C) center (-2,-1) , a=1, b=3 D) center (-2,-1) , a=3, b=1$
C) center $(-2,-1) , a=1, b=3$
$Graph the ellipse. Give the coordinates of the center, as well as the values of a and b . - \frac{(x+2) ^{2}}{9}+(y+1) ^{2}=1 A) center (-2,-1) , a=3, b=1 B) center (-2,-1) , a=1, b=3 C) center (-2,-1) , a=1, b=3 D) center (-2,-1) , a=3, b=1$
D) center $(-2,-1) , a=3, b=1$
$Graph the ellipse. Give the coordinates of the center, as well as the values of a and b . - \frac{(x+2) ^{2}}{9}+(y+1) ^{2}=1 A) center (-2,-1) , a=3, b=1 B) center (-2,-1) , a=1, b=3 C) center (-2,-1) , a=1, b=3 D) center (-2,-1) , a=3, b=1$

Graph the Ellipse aaa And bbb - (x+2)29+(y+1)2=1\frac{(x+2)^{2}}{9}+(y+1)^{2}=19(x+2)2​+(y+1)2=1 A) Center (−2,−1),a=3,b=1 (-2,-1), a=3, b=1 (−2,−1),a=3,b=1

Multiple Choice

Correct Answer:VerifiedUnlock this answer nowGet Access to more Verified Answers free of chargeAccess For Free

Graph the Ellipse $a$ And $b$
- $\frac{(x+2)^{2}}{9}+(y+1)^{2}=1$ A) Center $(-2,-1), a=3, b=1$

Correct Answer:
Verified
Unlock this answer now
Get Access to more Verified Answers free of charge