Solved

Find the Standard-Form Equation of the Hyperbola Whose Graph Is y216x225=1\frac{y^{2}}{16}-\frac{x^{2}}{25}=1

Question 88

Multiple Choice

Find the standard-form equation of the hyperbola whose graph is shown.
- Find the standard-form equation of the hyperbola whose graph is shown. -   A)   \frac{y^{2}}{16}-\frac{x^{2}}{25}=1  B)   4 y^{2}-5 x^{2}=1  C)   16 y^{2}-25 x^{2}=1  D)   \frac{y^{2}}{4}-\frac{x^{2}}{5}=1


A) y216x225=1\frac{y^{2}}{16}-\frac{x^{2}}{25}=1
B) 4y25x2=14 y^{2}-5 x^{2}=1
C) 16y225x2=116 y^{2}-25 x^{2}=1
D) y24x25=1\frac{y^{2}}{4}-\frac{x^{2}}{5}=1

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions