Suppose $f(x)=2(x-3)$ And Suppose That $g$ Is an Invertible Function Such That $g^{-1}(x)=\frac{1-9 x}{2}$

Short Answer

Suppose $f(x)=2(x-3)$ and suppose that $g$ is an invertible function such that $g^{-1}(x)=\frac{1-9 x}{2}$ . Find $f(g(x))$ and write it in the form $a x+b$ .