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The Height of an Object Above the Ground Is Described f(t)=2.3t2−14t+4f(t)=2.3 t^{2}-14 t+4

Question 34

Short Answer

The height of an object above the ground is described by the function f(t)=2.3t2−14t+4f(t)=2.3 t^{2}-14 t+4 .
a) What is the initial height of the object at time t=0t=0 ?
b) When does the object have height 2 ?

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