The Vertex Form Of $f(x)=x^{2}+4 x-1$ Is $f(x)=(x+a)^{2}-b$ , Where $a=$ ----------- And $b=$

Short Answer

The vertex form of $f(x)=x^{2}+4 x-1$ is $f(x)=(x+a)^{2}-b$ , where $a=$ ----------- and $b=$ ------------