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Let g(x)=6x+6g(x)=\frac{6}{x}+6 Does g−1(x)=6x−6g^{-1}(x)=\frac{6}{x-6}

Question 62

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Let g(x)=6x+6g(x)=\frac{6}{x}+6 . Does g−1(x)=6x−6g^{-1}(x)=\frac{6}{x-6} ?

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