Let $f(x)=\left(x^{2}+1\right)(x+2)$ And $g(x)=(x-1)\left(x^{2}-4\right)$ Find a Simplified Formula For a Simplified $h(x)=\frac{5 f(x)}{17 g(x)}$

Short Answer

Let $f(x)=\left(x^{2}+1\right)(x+2)$ and $g(x)=(x-1)\left(x^{2}-4\right)$ . Find a simplified formula for $h(x)=\frac{5 f(x)}{17 g(x)}$ .