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- F=95C+32F=\frac{9}{5} C+32 For CC A) C=95(F32)C=\frac{9}{5}(F-32) B) C=5F32C=\frac{5}{F-32} C) C=F329C=\frac{F-32}{9} D) C=59(F32)C=\frac{5}{9}(F-32)

Question 171

Multiple Choice

Solve.
- F=95C+32F=\frac{9}{5} C+32 for CC


A) C=95(F32) C=\frac{9}{5}(F-32)
B) C=5F32C=\frac{5}{F-32}
C) C=F329C=\frac{F-32}{9}
D) C=59(F32) C=\frac{5}{9}(F-32)

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