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Solve Using the Addition and Multiplication Principles x2+1410\frac{x}{2}+14 \leq 10 A) {xx<6}\{x \mid x<-6\}

Question 169

Multiple Choice

Solve using the addition and multiplication principles.
- x2+1410\frac{x}{2}+14 \leq 10


A) {xx<6}\{x \mid x<-6\}
B) {xx6}\{x \mid x \leq 6\}
C) {xx8}\{x \mid x \leq-8\}
D) {xx8}\{x \mid x \geq-8\}

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