Question 1

Solve.
-When Maria finished medical school she had a student loan. She repaid $\$ 27,000$ of the loan within two years of graduating. That was $\frac{1}{2}$ of the total amount she owed. Write and solve an equation to determine the total amount, $x$, of the student loan.

Accepted Answer

A)    27,000=12x;$54,00027,000=\frac{1}{2} x ; \$ 54,00027,000=21​x;$54,000 
B)    27,000=12x;$24,30027,000=\frac{1}{2} x ; \$ 24,30027,000=21​x;$24,300 
C)    27,000⋅12=x;$54,00027,000 \cdot \frac{1}{2}=x ; \$ 54,00027,000⋅21​=x;$54,000 
D)    27,000⋅12=x;$24,30027,000 \cdot \frac{1}{2}=x ; \$ 24,30027,000⋅21​=x;$24,300 A

Question 2

Translate the sentence to an equation.
-1.7 minus $q$ is equal to 10 .

Accepted Answer

A)    q−1.7=10q-1.7=10q−1.7=10 
B)    1.7−10=q1.7-10=q1.7−10=q 
C)    1.7−q=1.71.7-q=1.71.7−q=1.7 
D)    1.7−q=101.7-q=101.7−q=10 D

Question 3

Translate the sentence to an equation then solve.
-q divided by 2 yields 10 .

Accepted Answer

A)    2q=10,q=82 q=10, q=82q=10,q=8 
B)    q2=10,q=20\frac{\mathrm{q}}{2}=10, \mathrm{q}=202q​=10,q=20 
C)    2q=10,q=52 q=10, q=52q=10,q=5 
D)    q2=10,q=15\frac{q}{2}=10, q=\frac{1}{5}2q​=10,q=51​ B

Question 4

Translate the sentence to an equation then solve.
-The product of 3 and $x$ is 7 .

Accepted Answer

A)    3x=7,x=43 x=7, x=43x=7,x=4 
B)    3x=7,x=373 x=7, x=\frac{3}{7}3x=7,x=73​ 
C)    x3=7,x=21\frac{x}{3}=7, x=213x​=7,x=21 
D)    3x=7,x=733 x=7, x=\frac{7}{3}3x=7,x=37​

Question 5

Solve.
-Bill paid $\$ 1.84$ for a phone call lasting 16 minutes. Write and solve an equation to find the price per minute, $x$. Round to the nearest cent.

Accepted Answer

A)    x16=$1.84;$29.44\frac{x}{16}=\$ 1.84 ; \$ 29.4416x​=$1.84;$29.44 
B)    x16=$1.84;$0.12\frac{\mathrm{x}}{16}=\$ 1.84 ; \$ 0.1216x​=$1.84;$0.12 
C)    16x=$1.84;$0.1216 x=\$ 1.84 ; \$ 0.1216x=$1.84;$0.12 
D)    16x=$1.84;$0.0716 x=\$ 1.84 ; \$ 0.0716x=$1.84;$0.07

Question 6

Solve the equation.
-$x-2 \frac{2}{5}=11$

Accepted Answer

A)    x=1325x=13 \frac{2}{5}x=1352​ 
B)    x=835x=8 \frac{3}{5}x=853​ 
C)    x=1335x=13 \frac{3}{5}x=1353​ 
D)    x=935x=9 \frac{3}{5}x=953​

Question 7

Evaluate the algebraic expression.
-$\frac{\mathrm{m}}{10}$, for $\mathrm{m}=2 \frac{2}{9}$

Accepted Answer

A)    19\frac{1}{9}91​ 
B)    29\frac{2}{9}92​ 
C)    14\frac{1}{4}41​ 
D)    13\frac{1}{3}31​

Question 8

Translate the word phrase into an algebraic expression.
-The product of 2 and $x$

Accepted Answer

A)    2x\frac{2}{x}x2​ 
B)    2−x2-x2−x 
C)    2+x2+x2+x 
D)    2x2 x2x

Question 9

Evaluate the expression.
-$9 x$, if $x=7.7$

Accepted Answer

A)   16.7
B)    9077\frac{90}{77}7790​ 
C)   1.3
D)   69.3

Question 10

Translate the word phrase into an algebraic expression.
-9 hours past time $x$

Accepted Answer

A)    9x9 x9x 
B)    9+x9+x9+x 
C)    9−x9-x9−x 
D)   9

Question 11

Identify the operation to perform to the equation to isolate the variable.
-$\frac{y}{2}=7$

Accepted Answer

A)   Multiply by 2
B)   Divide by 2
C)   Divide by 7
D)   Multiply by 7

Question 12

Indicate whether the value of $x$ shown is a solution to the given equation.
-$3 x=\frac{1}{3}, x=\frac{1}{9}$

Accepted Answer

A) True 
 B)False

Question 13

Write an equation. Then, solve and check.
-A pancake recipe calls for $2 \frac{1}{5}$ pounds of flour. David already has $1 \frac{2}{5}$ pounds of flour. How many more pounds does he need?

Accepted Answer

A)    x−125=215;x=335lbx-1 \frac{2}{5}=2 \frac{1}{5} ; x=3 \frac{3}{5} \mathrm{lb}x−152​=251​;x=353​lb 
B)    125+x=215;x=45lb1 \frac{2}{5}+\mathrm{x}=2 \frac{1}{5} ; \mathrm{x}=\frac{4}{5} \mathrm{lb}152​+x=251​;x=54​lb 
C)    x−125=215;x=45lbx-1 \frac{2}{5}=2 \frac{1}{5} ; x=\frac{4}{5} \mathrm{lb}x−152​=251​;x=54​lb 
D)    125+x=215;x=335lb1 \frac{2}{5}+\mathrm{x}=2 \frac{1}{5} ; \mathrm{x}=3 \frac{3}{5} \mathrm{lb}152​+x=251​;x=353​lb

Question 14

Solve.
-You plan to purchase a bike costing $\$ 795$. Write an equation that could be used to find the amount $\mathrm{m}$, that you must save per month in order to buy the bike 5 months from now.

Accepted Answer

A)    m=5⋅795\mathrm{m}=5 \cdot 795m=5⋅795 
B)    5 m=7955 \mathrm{~m}=7955 m=795 
C)    5+m=7955+m=7955+m=795 
D)    m5=795\frac{m}{5}=7955m​=795

Question 15

Solve the equation.
-$x-1.571=2.084$

Accepted Answer

A)    x=0.613x=0.613x=0.613 
B)    x=3.655x=3.655x=3.655 
C)    x=0.513x=0.513x=0.513 
D)    x=2.655x=2.655x=2.655

Question 16

Solve the equation.
-$n+7=16$

Accepted Answer

A)    n=−9n=-9n=−9 
B)    n=16n=16n=16 
C)    n=23n=23n=23 
D)    n=9n=9n=9

Question 17

Translate the sentence to an equation. Do not solve.
-The difference between 9 and y is $2 \frac{4}{7}$.

Accepted Answer

A)    9=y−2479=y-2 \frac{4}{7}9=y−274​ 
B)    9y=247\frac{9}{y}=2 \frac{4}{7}y9​=274​ 
C)    y−9=247y-9=2 \frac{4}{7}y−9=274​ 
D)    9−y=2479-\mathrm{y}=2 \frac{4}{7}9−y=274​

Question 18

Complete the table.
-

Accepted Answer

A)   
B)   
C)   
D)

Question 19

Translate the sentence to an equation.
-The sum of 8 and $t$ is 28 .

Accepted Answer

A)    8+t=88+\mathrm{t}=88+t=8 
B)    8+28=t8+28=\mathrm{t}8+28=t 
C)    28+t=828+\mathrm{t}=828+t=8 
D)    8+t=288+t=288+t=28

Question 20

Solve.
-Write an expression for the sum of the lengths of the sides of the triangles shown.

Accepted Answer

A)    3+7+x3+7+x3+7+x  or  10+x10+x10+x 
B)    x+4x+4x+4 
C)    7+x7+x7+x 
D)   10

Exam 4: Basic Algebra: Solving Simple Equations

Solve. -When Maria finished medical school she had a student loan. She repaid $\$ 27,000$ of the loan within two years of graduating. That was $\frac{1}{2}$ of the total amount she owed. Write and solve an equation to determine the total amount, $x$ , of the student loan.

Translate the sentence to an equation. -1.7 minus $q$ is equal to 10 .

Translate the sentence to an equation then solve. -q divided by 2 yields 10 .

Translate the sentence to an equation then solve. -The product of 3 and $x$ is 7 .

Solve. -Bill paid $\$ 1.84$ for a phone call lasting 16 minutes. Write and solve an equation to find the price per minute, $x$ . Round to the nearest cent.

Solve the equation. - $x-2 \frac{2}{5}=11$

Evaluate the algebraic expression. - $\frac{\mathrm{m}}{10}$ , for $\mathrm{m}=2 \frac{2}{9}$

Translate the word phrase into an algebraic expression. -The product of 2 and $x$

Evaluate the expression. - $9 x$ , if $x=7.7$

Translate the word phrase into an algebraic expression. -9 hours past time $x$

Identify the operation to perform to the equation to isolate the variable. - $\frac{y}{2}=7$

Indicate whether the value of $x$ shown is a solution to the given equation. - $3 x=\frac{1}{3}, x=\frac{1}{9}$

Write an equation. Then, solve and check. -A pancake recipe calls for $2 \frac{1}{5}$ pounds of flour. David already has $1 \frac{2}{5}$ pounds of flour. How many more pounds does he need?

Solve. -You plan to purchase a bike costing $\$ 795$ . Write an equation that could be used to find the amount $\mathrm{m}$ , that you must save per month in order to buy the bike 5 months from now.

Solve the equation. - $x-1.571=2.084$

Solve the equation. - $n+7=16$

Translate the sentence to an equation. Do not solve. -The difference between 9 and y is $2 \frac{4}{7}$ .

Complete the table. -

Translate the sentence to an equation. -The sum of 8 and $t$ is 28 .

Solve. -Write an expression for the sum of the lengths of the sides of the triangles shown.

Exam 4: Basic Algebra: Solving Simple Equations

Solve. -When Maria finished medical school she had a student loan. She repaid $27,000\$ 27,000$27,000 of the loan within two years of graduating. That was 12\frac{1}{2}21​ of the total amount she owed. Write and solve an equation to determine the total amount, xxx , of the student loan.

Translate the sentence to an equation. -1.7 minus qqq is equal to 10 .

Translate the sentence to an equation then solve. -q divided by 2 yields 10 .

Translate the sentence to an equation then solve. -The product of 3 and xxx is 7 .

Solve. -Bill paid $1.84\$ 1.84$1.84 for a phone call lasting 16 minutes. Write and solve an equation to find the price per minute, xxx . Round to the nearest cent.

Solve the equation. - x−225=11x-2 \frac{2}{5}=11x−252​=11

Evaluate the algebraic expression. - m10\frac{\mathrm{m}}{10}10m​ , for m=229\mathrm{m}=2 \frac{2}{9}m=292​

Translate the word phrase into an algebraic expression. -The product of 2 and xxx

Evaluate the expression. - 9x9 x9x , if x=7.7x=7.7x=7.7

Translate the word phrase into an algebraic expression. -9 hours past time xxx

Identify the operation to perform to the equation to isolate the variable. - y2=7\frac{y}{2}=72y​=7

Indicate whether the value of xxx shown is a solution to the given equation. - 3x=13,x=193 x=\frac{1}{3}, x=\frac{1}{9}3x=31​,x=91​

Write an equation. Then, solve and check. -A pancake recipe calls for 2152 \frac{1}{5}251​ pounds of flour. David already has 1251 \frac{2}{5}152​ pounds of flour. How many more pounds does he need?

Solve. -You plan to purchase a bike costing $795\$ 795$795 . Write an equation that could be used to find the amount m\mathrm{m}m , that you must save per month in order to buy the bike 5 months from now.

Solve the equation. - x−1.571=2.084x-1.571=2.084x−1.571=2.084

Solve the equation. - n+7=16n+7=16n+7=16

Translate the sentence to an equation. Do not solve. -The difference between 9 and y is 2472 \frac{4}{7}274​ .